A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is `mu` , the shortest distance in which the car can be stopped is

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyre and the road is mu, the shortest distance in which the car can be stopped is.

Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10 ms^(-1)]

Consider, a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyre and the road is 0.5, the shortest distance in which the car can be stopped is (Take g=10 //s^(2) )

Consider a car moving along a straight horizontal road with a speed of 72 km / h . If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10ms^(-2)]

An automobile is moving on a straight horizontal road with a speed u. If the coefficient of static friction between the tyres and the road is mu_(s) what is the shortest distance in which the automobiles can be stopped ?

Consider a car moving along a straight horizontal road with a speed of 36 km/h. If the coefficient of static friction between road and tyers is 0.4, the shortest distance in which the car can be stopped is (Take g=10 m//s2)

Consider a car moving along a straight horizontal road with a speed of 36 km/h. If the coefficient of static friction between road and tyers is 0.4, the shortest distance in which the car can be stopped is (Take g=10 m//s2)

An automobile is moving on a horizontal road with a speed of v.If teh coeficient of friction between the tyres nd the road is mu ,show that the shortest distance in whih the automobie can be stopped is v^2l2mug .

An automobile is moving on a horizontal road with a speed upsilon If the coefficient of friction between the tyres and the road is mu show that the shortest distance in which the automobile can be stooped is upsilon^(2)//2 mu g .