At what temperature the root mean square velocity is equal to escape velocity from the surface of earth for hydrogen and for oxygen ? Given radius of earth ` = 6.4 xx 10^(6) m , g = 9.8 ms^(-2)`. Boltzmann constant `= 1.38 xx 10^(-23) J "molecule"^(-1)`.

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

Calculate the mass of the earth. Given radius of the earth =6.4xx10^-6 m and g = 9.8 m//s^2

At what temperature will the average velocity of oxygen molecules be sufficient to escape from the earth. Given mass of oxygen molecule = 5.34 xx 10^(-26) kg . Boltzmann constant, k = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1) . Escape velocity of earth = 11.0 km s^(-1) .

At what temperature will the average velocity of oxygen molecules be sufficient to escape from the earth. Given mass of oxygen molecule = 5.34 xx 10^(-26) kg . Boltzmann constant, k = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1) . Escape velocity of earth = 11.0 km s^(-1) .

Calculate the escape velocity of an atmospheric particle 1000 km above the surface of the earth. Given R = 6.4 xx 10^(6)m and g = 9.8 ms^(-2) .

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere ? (Given : Mass of oxygen molecule (m) = 2.76 xx 10^(-26) kg , Boltzmann's constant k_B = 1.38 xx 10^(-23) JK^(-1) )

At what temperature will the average velocity of oxygen molecules be sufficient so as to escape from the earth ? Escape velocity of earth is 11.0 kms^(-1) and mass of one molecule of oxygen is 5.34xx10^(-26) kg. Boltzmann constant =1.38xx10^(-23) " J molecule"^(-1) K^(-1) .