By what acceleration the boy must go up so that `100kg` block remains stationary on the wedge. The wedge is fixed and is smooth `(g =10m//s^(2))`
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In the arrangement shown, by what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. Take g = 10m//s^2

A block of mass m is placed on the rough incline of a wedge of mass M and inclination alpha to the horizontal. Calculate the maximum and minimum acceleration that can be imparted to the wedge so that the block may remain stationary relative to the wedge. The coefficient iof friction between the block and the wedge is mu .

All surfaces are smooth in the adjoining figure. Find F such that block remains stationary with respect to wedge.

All surfaces shown in the figure are frictionless. A block of mass 2 kg is kept on a wedge of mass 10 kg. If the mass m remains stationary w.r.t wedge , the magnitude of force P is ( g = 10 m//s^(2))

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))

All surface are smooth in following figure. Find F , such that block remain stationary with respect to wedge.

All surface are smooth in following figure. Find F , such that block remain stationary with respect to wedge.