If `theta in (0, 2pi)` and `2sin^2theta - 5sintheta + 2 > 0`, then the range of `theta` is

If 2 sin^2 theta - 5 sin theta + 2 gt 0, theta in (0,2pi)," then" theta in :

If 0

The set of values of theta satisfying the inequatioin 2sin^(2)theta-5sintheta+2 gt 0, where o lt theta lt 2pi , is

The set of values of theta satisfying the inequatioin 2sin^(2)theta-5sintheta+2 gt 0, where o lt theta lt 2pi , is

The set of values of theta satisfying the inequatioin 2sin^(2)theta-5sintheta+2 gt 0, where o lt theta lt 2pi , is

The set of values of theta satisfying the inequatioin 2sin^(2)theta-5sintheta+2 gt 0, where o lt theta lt 2pi , is

The set of values of theta satisfying the inequatioin 2sin^(2)theta-5sintheta+2 gt 0, where o lt theta lt 2pi , is

The set of values of theta satisfying the inequation 2sin^(2)theta-5sin theta+2>0, when theta in(0,2 pi) is

If : 0 lt theta lt pi/2 and sin 7theta + sin 4 theta + sin theta=0 , then : theta =

int_0^(pi//2)(theta/sintheta)^2d theta=