[" The area of the rectangle formed by the perpendicular from centre of "(x^(2))/(9)],[" the point whose eccentric angle is "(pi)/(4)" equals "]

The area of the rectangle formed by the perpendicular from centre of (x^(2))/(9)+(y^(2))/(4)=1 to the tangents area normal the point where occeses angle is (pi)/(4) equals

The area of the rectangle formed by the perpendiculars from the centre of the ellipse (x^(2))/(9)+(y^(2))/(4)=1 to the tangent and normal at the point whose eccentric angle is (pi)/(4) , is :

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles (pi)/(4) is

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles pi/4 is

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles pi/4 is

The equation of the normal to the ellipse (x^(2))/(4)+(y^(2))/(2)=1 at the point whose eccentric angle is (pi)/(4) is

If area of rectangle formed by the perpendiculars drawn from centre of ellipse (x^(2))/(9)+(y^(2))/(16)=1 to the tangent and normal at the point (P((3)/(sqrt(2)),2sqrt(2))) on ellipse is ((a)/(b)) (where a and b are coprime numbers) then (a-3b) equals

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)