An ideal gas has initial volume V and pressure p. In doubling its volume the minimum work done will be in the process (of the given processes)

An ideal gas has initial volume V and pressure P . To triple it a volume the minimum work done will be in

An ideal gas has initial pressure of 3 presssure units and an initial volume units the table gives the final pressure and volume of the gas ( in those same units ) in five processes which processes start and end on the same isotherm ?

An ideal gas undergoes isobaric expansion at pressure P from volume V_1 to V_2 the work done is :

An ideal gas undergoes a process P→Q→R as shown in pressure (p) - volume (v) diagram.The work done by the gas is

One mole of an ideal gas at 300 K expands from V to 2V volume, then work done W in this process will be …

The pressure of an ideal gas varies with volume as P= aV, where a is a constant. One mole of the gas is allowed to undergo expansion such that its volume becomes ‘m’ times its initial volume. The work done by the gas in the process is

n moles of an ideal mono atomic gas is initially at pressure 32 P_(0) and volume V_(0) . Its volume is doubled by an isobaric process. After this the gas is adiabatically expanded so as to make its volume 16V_(0) . Now the gas is isobarically expanded. Finally, the gas is made to return to its initial state by an isothermal process. (a) Represent the process on a P–V diagram. (b) Calculate work done by the gas in one cycle.

An ideal gas compressed to half its initial volume by means of several processes. Which of the process results in the maximum work done on the gas?