`((30)/(0)) ((30)/(10)) - ((30)/(1)) ((30)/(11)) + ((30)/(2)) ((30)/(12)) + …. + ((30)/(2)) ((30)/(30))` is equal to

The value of ((30),(0))((30),(10))+((30),(1))((30),(11))+((30),(2))((30),(12))+ . . .((30),(20))((30),(30)) is:

The value of {:((30), (0))((30), (10))-((30), (1))((30),( 11)) +((30), (2))((30), (12))+....+((30), (20))((30), (30)):}

The value of ((30), (0))((30), (10))-((30), (1))((30),( 11)) +((30), (2))((30), (12))+.....+((30), (20))((30), (30))= ^60 C 20 b. ^30 C 10 c. ^60 C 30 d. ^40 C 30

Find the value of ((30),(0))((30),(10))-((30),(1))((30),(11))+((30),(2))((30),(12))+....+((30),(10))((30),(20))

({:(30),(0):})({:(30),(10):})-({:(30),(1):})({:(30),(11):}) + ... + ({:(30),(20):})({:(30),(30):}) is equal to

The probability that out of 10 person, all born in June, at least two have the same birthday is (a) (""^(30 C_(10)))/((30)^(10)) (b) 1 - (""^(30) C_(10))/(30!) (c) ((30)^(10) - ""^(30) P_(10))/((30)^(10)) (d) None of these

If the value of the sum 29(.^(30)C_(0))+28(.^(30)C_(1))+27(.^(30)C_(2))+…….+1(.^(30)C_(28))+0.(.^(30)C_(29))-(.^(30)C_(30)) is equal to K.2^(32) , then the value of K is equal to

If ((n),(r)) denotes nC_r , then Evaluate 2^15((30),(0))((30),(15))-2^14((30),(1))((29),(14))+2^13 ((30),(2))((28),(13))...............-((30),(15))((15),(0))

The value of ((30), (0))((30), (10))-((30), (1))((30),( 11)) +(30 2)(30 12)++(30 20)(30 30)= ^60 C 20 b. ^30 C 10 c. ^60 C 30 d. ^40 C 30