A simple pendulum is vibrating with an angular amplitude of `90^(@)` as shown in figure. For what value of `alpha` (angle between string and vertical) during its motion, the total acceleration is directed horizontally ?

A simple pendulum is oscillating with an angular amplitude of 90^(@) as shown in the figure. The value of theta for which the resulting acceleration of the bob is directed (i) vertically downward, (ii) vertically upward and (iii) horizontally is

a simple pendulum with a bob of mass m savings with an angular amplitude of 40^(@) . When its angular displacement is 20^(@) , the tension in the strings is-

A simple pendulum is oscillating with angular displacement 90^(@) For what angle with vertical the acceleration of bob direction horizontal?

A simple pendulum is oscillating with angular displacement 90^(@) For what angle with vertical the acceleration of bob direction horizontal?

A simple pendulum 4m long swing with an amplitude of 0.2m . What is its acceleration at the ends of its path?

A simple pendulum swings with angular amplitude theta . The tension in the string when it is vertical is twice the tension in its extreme position. Then, cos theta is equal to

A simple pendulum swings with angular amplitude theta . The tension in the string when it is vertical is twice the tension in its extreme position. Then, cos theta is equal to

A simple pendulum with a bob of mass 'm' swings with angular amplitude of 60^@ . When its angular displacement is 30^@ , the tension in the strings would be