Potential energy of a satellite having mass `m` and rotating at a height of `6.4xx10^(6)m` from the earth surface is

The gravitational potential energy of a rocket of mass 200kg at a height of 10^(7) m from the earth's surface is 10^(9) s. The potential energy of the rocket at a height of 26.4xx10^(6) m from the surface of earth is:

Find the gravitational potential energy of a body of mass 10 kg when it is at a height of 6400 km from the earth's surface. [M (earth) = 6xx 10^24 kg, R(earth) =6400 km]

The potential energy of a satellite of mass m revolving at height R above the surface of the earth where R= radius of earth is

Calculate (i) kinetic energy (ii) potential energy and (iii) total energy of a satellite of mass 200 kg orbiting around the earth in an orbit of height 100 km from the surface of earth. Given, mass of earth = 10^(25) kg ,radius of earth = 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth's surface. M_E = 6 xx 10^24 kg R_E = 6.4 10^6 m