Home
Class 12
PHYSICS
In the Moseley relation, sqrt(v)=a(Z-b) ...

In the Moseley relation, `sqrt(v)=a(Z-b)` which will have the greater value for the constant a for `K_(alpha)` or `K_(beta)` transition?

Promotional Banner

Similar Questions

Explore conceptually related problems

According to Moseley sqrt(v)= a (z - b) , then v is :

In Moseley's law sqrt(v)=a(z-b), the volue of the screening constant for K-series and L-series of X-rays are respectively

In Moseley's law sqrt(v)=a(z-b), the volue of the screening constant for K-series and L-series of X-rays are respectively

Find the constants a and b in Moseley's equation sqrt v=a(Z- b) from the following data.

Find the constants a and b in Moseley's equation sqrt v=a(Z- b) from the following data.

The constant 'a' Mosely's law sqrt(v) = a(Z-b) for k_(alpha)X- rays is related to Rydberg constant R as ( 'c' is the speed of light)

According to Moseley's law, the ratio of the slope of graph between sqrtf and Z for K_beta and K_alpha is

According to Moseley's law, the ratio of the slope of graph between sqrtf and Z for K_beta and K_alpha is

The constant 'a' Mosely's law sqrt(v) - a(Z-b) for k_(alpha)X- rays is related to Rydberg constant R as ( 'c' is the speed of light)

The constant 'a' Mosely's law sqrt(v) - a(Z-b) for k_(alpha)X- rays is related to Rydberg constant R as ( 'c' is the speed of light)