In X-ray tube , when the accelerating voltage `V` is halved, the difference between the wavelength of `K_(alpha)` line and minimum wavelength of continuous X-ray spectrum

Deltalambda is the difference between the wavelength of K_(alpha) line and the minimum wavelength of the continuous X-rays spectrum when the X-ray tube is operated at a voltage V. If the operating voltage is changed to V/3 , the above difference is Deltalambda Then,

When the voltage applied to an X-ray tube increased from V_(1)=15.5kV to V_(2)=31kV the wavelength interval between the K_(alpha) line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of 1.3 . If te atomic number of the element of the target is z. Then the value of (z)/(13) will be: (take hc=1240eVnm and R=1xx(10^(7))/(m))

When the voltage applied to an X-ray tube increased from V_(1)=15.5kV to V_(2)=31kV the wavelength interval between the K_(alpha) line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of 1.3 . If te atomic number of the element of the target is z. Then the value of (z)/(13) will be: (take hc=1240eVnm and R=1xx(10^(7))/(m))

An X-ray tube has nickel as target. The wavelength difference between the ka X-ray and the cut-off wavelength of continuous X-ray spectrum is 84 pm. Find the accelerating voltage applied in the X-ray tube. [Take hc = 12400 eV Å ]