The equation of a wave on a string of linear mass density `0.04 kg m^(-1)` is given by `y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))]`. The tension in the string is :

The equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

The equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

the equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

The equation of a transverse wave along a stretched string is given by y = 15 sin 2pi ((t)/(0.04) - (x)/(40)) cm . The velocity of the wave is

The equation of a transverse wave propagating through a stretched string is given by y=2 sin 2pi ((t)/(0.04) -x/(40)) where y and x are in centimeter and t in seconds. Find the velocity of the wave, maximum velocity of the string and the maximum acceleration.

The equation of a progressive wave is given by, y = 3 sin pi ((t)/(0.02) - (x)/(20)) m . Then the frequency of the wave is

A string wave equation is given y = 0.002 sin(300t-15x) and mass density is (mu=(0.1kg)/(m)) . Then find the tension in the string

A string wave equation is given y = 0.002 sin(300t-15x) and mass density is (mu=(0.1kg)/(m)) . Then find the tension in the string