`(sin 4theta + sin 5theta)/(cos3theta+1) = sin(mtheta) + sin(ntheta)` where `m, n inN`, then (m + n) equals.

(sin4 theta+sin5 theta)/(cos3 theta+1)=sin(m theta)+sin(n theta) where m,n in N, then (m+n) equals.

5. sin m theta=sin n theta

sin theta cos ^ (3) theta-cos theta sin ^ (3) theta = (1) / (4) sin4 theta

cos m theta-sin n theta=0

Prove that : (sin 5theta + sin 3theta)/(cos 5theta + cos 3theta) = tan 4theta

If cos m theta = sin n theta , then theta =

If ((1 + cos theta + i sin theta ) /(i+ sin theta + i cos theta ))= cos ntheta + i sin n theta then n is equal to :

If sin theta + costheta = m and sin theta - cos theta = n , then

If sin theta + costheta = m and sin theta - cos theta = n , then