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If alpha=tan^(-1)((4x-4x^3)/(1-6x^2+x^2)...

If `alpha=tan^(-1)((4x-4x^3)/(1-6x^2+x^2)),beta=2sin^(-1)((2x)/(1+x^2))` and `tanpi/8=k ,` then (a) `alpha+beta=pi` for `x in [(1,1)/k]` (b)`alpha+beta` for `x in (-k , k)` (c) `alpha+beta=pi` for`x in [(1,1)/k]` (d) `alpha+beta=0` for `x in [-k , k]`

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