A proton enters a magnetic field with a velocity of `2.5 xx10^(7)ms^(-1)` making an angle `30^(@)` with the magnetic field. The force on the proton is `(B=25T)`

A proton enters a magnetic field with a velocity of 2.5 xx 10^7 ms^-1 making angles 30^@ with the magnetic field. What is the force on the proton ? Given that B = 2.5 T .

A proton enters a magnetic field of flux density 1.5 T with a velocity of 2 xx 10^(7)ms^(-1) at an angle of 30° with the field. The force on the proton is [e_(p)=1.6 xx 10^(-19)C]

A proton enters a magnetic field of flux density 1.5 T with a velocity of 20 xx 10^(7)ms^(-1) at an angle of 30° with the field. The force on the proton is [e_(p)=1.6xx10^(-19)C]

A proton enters a magnetic field of flux density 2.0 weber/m^2 with a velocity of 2 xx 10^7ms^1 at an angle of 30^@ with the field,the force on the proton will be

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is

A proton enters a magnetic field of flux density 2*5T with a speed of 1*5xx10^7ms^-1 at an angle of 30^@ with the field, Find the force on the proton.