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Angle between the tangents to the curve ...

Angle between the tangents to the curve `y=x^2-5x+6` at the points `(2,0) and (3,0)` is : (a) `pi/3` (b) `pi/2` (c) `pi/6` (d) `pi/4`

Text Solution

Verified by Experts

Equation of given curve is,
`y = x^2-5x+6`
So, `dy/dx = 2x-5`
We know at any point of curve slope of tangent of is `dy/dx`.
So, at `(2,0), dy/dx = m_1 = -1`
At `(3,0), dy/dx = m_2 = 1`
`:.m_1*m_2 = -1`
That means both these tangents are perpendicular.
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