Slope of a line passing through `P(2,3)` and intersecting the line, `x+y=7` at a distance of `4` units from `P`, is

If a line is passing through p(2,3) which intersects the line x+y=7 at a distance of four units from P. Then the slope of line is

The slope of line passing through A(2, 3), B(4,7)

A line passing through A(1, -2) has slope 1. The points on the line at a distance of 4sqrt(2) unit from A are

A line passing through the point P (1, 2) meets the line x+y=7 at the distance of 3 units from P. Then the slope of this line satisfies the equation

A line passing through the point P(1,2) meets the line x+y=7 at the distance of 3 units from P. Then the slope of this line satisfies the equation :

A line passing through P(1,2) intersect the line x+y+3=0 in point A such that AP=3sqrt(2) then slope of AP is

Find the equation of a line passing through the intersection of the lines y=2(x-1) and y=3x-5 and which is at a distance of (7)/(sqrt(2)) units from origin.

Find the equation of a line passing through the intersection of the lines y=2(x-1) and y=3x-5 and which is at a distance of (7)/(sqrt(2)) units from origin.

The slope of the line passing through A(-2,3) is -4/3 .The points on the line that are 10 units away from A are