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x^2+10^-8 x-10^-14=0 How to solve ?...

`x^2+10^-8 x-10^-14=0` How to solve ?

Text Solution

Verified by Experts

In the given equation,
`x^2+10^(-8)x-10^(-14) = 0`
`a = 1, b = 10^(-8), c = -10^(-14)`
`:. x = (-b+-sqrt(b^2-4ac))/(2a)`
`=> x = (-10^(-8)+-sqrt(10^(-16)-4(-10^(-14))))/2`
`=>x = (-10^(-8)+-sqrt(10^(-14)(1/100+4)))/2`
`=>x = (-10^(-8)+-sqrt(10^(-16)(401)))/2`
`=>x = (-10^(-8)+-(10^(-8))sqrt((401)))/2`
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