" If "Delta_(1)=|[x,b,b],[a,x,b],[a,a,x]|,Delta_(2)=|[x,b],[a,x]|" then "=

Delta_1 = |[x,b,b], [a,x, b] ,[a, a, x]| and Delta_2 = |[x,b],[a,x]| show that d(Delta_1)/ dx = 3 Delta_2

If Delta_1=|[x, b, b],[ a, x, b],[ a, a, x]| a n d Delta_2=|[x, b],[ a, x]| are the given determinants, then Delta_1=3(Delta_2)^2 b. d/(dx)(Delta_1)=3Delta_2 c. d/(dx)(Delta_1)=3(Delta_2)^2 d. Delta_1=3(Delta_2)^ (3//2)

If Delta_(1)=|(x,b,b),(a,x,b),(a,a,x)|andDelta_(2)=|(x,b),(a,x)| are the given determinants, then a) Delta_(1)=3(Delta_(2))^(2) b) (d)/(dx)(Delta_(1))=3Delta_(2) c) (d)/(dx)(Delta_(1))=3(Delta_(2))^(2) d) Delta_(1)=3Delta_(2)^(3//2)

If Delta_(1)=det[[x,b,ba,x,ba,a,x]] and Delta_(2)=det[[x,ba,x]] are

If Delta_1=|{:(x,b,b),(a,x,b),(a,a,x):}|and Delta_2=|{:(x,b),(a,x):}| are given determinants then,

Delta_1=|(x,b,a),(a,x,b),(a,a,x)|,Delta_2=|(x,b),(a,x)| are the given determinants , then :

Delta_(1)=|{:(x,b,b),(a,x,b),(a,a,x):}| and Delta_(2)=|{:(x,b),(a,x):}| are the given determinations then