The area bounded by the two branches of curve `(y-x)^2=x^3` and the straight line `x=1` is `1/5s qdotu n i t s` (b) `3/5s qdotu n i t s` `4/5s qdotu n i t s` (d) `8/4s qdotu n i t s`

The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is (a) 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is (a) 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

The area bounded by the curves y=x e^x ,y=x e^(-x) and the line x=1 is 2/e s qdotu n i t s (b) 1-2/e s qdotu n i t s 1/e s qdotu n i t s (d) 1-1/e s qdotu n i t s

The area bounded by the curves y=x e^x ,y=x e^(-x) and the line x=1 is 2/e s qdotu n i t s (b) 1-2/e s qdotu n i t s 1/e s qdotu n i t s (d) 1-1/e s qdotu n i t s

The area bounded by the curves y=x e^x ,y=x e^(-x) and the line x=1 is 2/e s qdotu n i t s (b) 1-2/e s qdotu n i t s 1/e s qdotu n i t s (d) 1-1/e s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area of the closed figure bounded by y=(x^2)/2-2x+2 and the tangents to it at (1,1/2)a n d(4,2) is 9/8s qdotu n i t s (b) 3/8s qdotu n i t s 3/2s qdotu n i t s (d) 9/4s qdotu n i t s