" If "f(x)=[[3-x^(2)times52],[sqrt(a+14)-1x-483,x>2]" and if "f(x)" has a local minima at "x=2" ,then the lear "

If f(x)={{:(3-x^(2)",",xle2),(sqrt(a+14)-|x-48|",",xgt2):} and if f(x) has a local maxima at x = 2, then greatest value of a is

If f(x)={{:(3-x^(2)",",xle2),(sqrt(a+14)-|x-48|",",xgt2):} and if f(x) has a local maxima at x = 2, then greatest value of a is

If f(x)={{:(3-x^(2)",",xle2),(sqrt(a+14)-|x-48|",",xgt2):} and if f(x) has a local maxima at x = 2, then greatest value of a is

(x)/(2)+(2)/(x) has local minima at

Let f(x)={1x-2l+a^(2)-9a-9 if x =2 if f(x) has local minimum at x=2, then

f(x) is cubic polynomial with f(x)=18 and f(1)=-1. Also f(x) has local maxima at x=-1 and f'(x) has local minima at x=0, then the distance between (-1,2) and (af(a)), where x=a is the point of local minima is 2sqrt(5)f(x) has local increasing for x in[1,2sqrt(5)]f(x) has local minima at x=1 the value of f(0)=15

Let f(x) be a polynomial of degree 3 having a local maximum at x=-1. If f(-1)=2,\ f(3)=18 , and f^(prime)(x) has a local minimum at x=0, then distance between (-1,\ 2)a n d\ (a ,\ f(a)), which are the points of local maximum and local minimum on the curve y=f(x) is 2sqrt(5) f(x) is a decreasing function for 1lt=xlt=2sqrt(5) f^(prime)(x) has a local maximum at x=2sqrt(5) f(x) has a local minimum at x=1

If f(x)=|x|+|x-1|-|x-2|, then-(A) f(x) has minima at x=1