Prove that : `sintheta/cos[3theta]+sin[3theta]/cos[9theta]+sin[9theta]/cos[27theta]=1/2[tan[27theta]-tan[theta]]`

Prove that sintheta/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)=1/2(tan27theta-tantheta)

Prove that : sin theta/cos(3theta) +sin (3theta)/cos (9theta) + sin(9theta)/cos( 27theta )= 1/2(tan27 theta -tan theta)

Prove that : (sin theta)/(cos[3 theta])+(sin[3 theta])/(cos[9 theta])+(sin[9 theta])/(cos[27 theta])=(1)/(2)[tan[27 theta]-tan[theta]]

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)

(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=

Show that, (sin theta)/(cos 3 theta) + (sin 3 theta)/(cos 9 theta) + (sin 9 theta)/(cos 27 theta) = 1/2 ( tan 27 theta - tan theta).

Prove that : (sin theta + sin 3theta + sin 5theta)/(cos theta + cos 3theta + cos 5theta) = tan 3theta

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=

Prove that : (cos theta)/(1-tan theta)+(sin theta)/(1-cot theta)=sin theta+cos theta

Prove that: :(1+sin theta-cos theta)/(1+sin theta+cos theta)=tan(theta)/(2)