" (a) "[" Sto "2x

Two trolleys of masses m and 3 m are connected by aspring. The spring is compressed and released the trolleys move off in opposite directions and come to rest after travelling distances s, and s, respectively. Assuming coefficient of friction is same for both the ratio of sto s_(1) to s_(2) is

(i) (x ^ (3) + 2x ^ (2) + 3x) -: 2x (ii) (10x-25) - :( 2x-5) (iii) (x (x + 1) (x + 2 ) (x + 3)) - :( x (x + 1))

Let fog (x) = log_(e) x and g(x) =(x^(4) -2x^(3) + 3x^(2) - 2x+2)/(2x^(2) - 2x + 1) Then , the domain of fog (x) is

Let f(x) = log_(e) x and g(x) =(x^(4) -2x^(3) + 3x^(2) - 2x+2)/(2x^(2) - 2x + 1) Then , the domain of fog (x) is

If g(x) = x^2 +x -2 and 1/2 (gof) (x) = 2x^2 - 5x +2 , then f(x) is equal to a) 2x -3 b) 2x+3 c) 2x^2 +3x +1 d) 2x^2 -3x -1

If f(x) = (x^2 -2x + 4)/(x^2+2x+4), x in R then range of function is

int(x^2-1)/(x^3sqrt(2x^4-2x^2+1))dx is equal to (a) (sqrt(2x^4-2x^2+1))/(x^3)+C (b) (sqrt(2x^4-2x^2+1))/x+C (c) (sqrt(2x^4-2x^2+1))/(x^2)+C (d) (sqrt(2x^4-2x^2+1))/(2x^2)+C

int(x^2-1)/(x^3sqrt(2x^4-2x^2+1))dx is equal to (a) (sqrt(2x^4-2x^2+1))/(x^3)+C (b) (sqrt(2x^4-2x^2+1))/x+C (c) (sqrt(2x^4-2x^2+1))/(x^2)+C (d) (sqrt(2x^4-2x^2+1))/(2x^2)+C

int(x^2-1)/(x^3sqrt(2x^4-2x^2+1))dx is equal to (a) (sqrt(2x^4-2x^2+1))/(x^3)+C (b) (sqrt(2x^4-2x^2+1))/x+C (c) (sqrt(2x^4-2x^2+1))/(x^2)+C (d) (sqrt(2x^4-2x^2+1))/(2x^2)+C

In a muscle fibre Ca^(++) is stoed in :-