((5)/(x)+5x)((25)/(x^(2))-25+25x^(2))

If x=3\ a n d\ y=-1, find the values of each of the using identity: (5/x+5x)((25)/(x^2)-25+25 x^2)

(5)/(2)x=(25)/(4)

(x-5)(x-6)=(25)/((24)^(2))

(x-1)/(x^(2)+5x)-(x+1)/(x^(2)-25)

5^(x)-24=(25)/(5^(x))

यदि 25 ^(-2x) = ( 5 ^((48)/(2)))/(5 ^((26)/(2)). 25 ^((19)/(2)) है तब x = ?

25 x e^(-5x)

If y=tan^(-1)((4x)/(1+5x^(2)))+tan^(-1)((2+3x)/(3-2x)) , then (dy)/(dx) is equal to a) (5)/(1+25x^(2)) b) (1)/(1+25x^(2)) c)0 d) (5)/(1-25x^(2))

int(dx)/(x-x^(2)-2.5)