48. A particle is moving in an isolated x-y plane. At an instan t ly ilms and acceleration (3-5m/s. At that instant what will be the radio curvature of its path? disha SRIIT NSC

A particle is moving in an isolated x-y plane. At an instant, the particle has velocity (4hati+4hatj)m//s and acceleration (3hati+5hatj)m//s^(2) . At that instant what will be the radius of curvature of its path ?

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves in x-y plane according to equations x = 4t^(2)+5t and 6y=5t The acceleration of the particle must be

A particle is moving with a uniform accerleration. Its displacement at any instant t is given by s=10t +4.9 t^2 . What is the uniform acceleration?

A particle moves in a circle of radius 2 m at a second what is its resultant (total ) acceleration at time t= 1 s ?

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is