[" An an A P "Y" a "=3.5" d "=0" add m "],[" then "a_(n)=a_(101)" will be "]

In an AP, if a = 3.5 , d = 0 and n = 101 , then a_(n) will be

In an AP, if a = 3.5 , d = 0 and n = 101 , then a_(n) will be

In an A.P., if a = 3.5, d = 0, n = 101, then find the value of a_(n) .

If a_(1) , a_(2) , a_(3),"………."a_(n) are in H.P. , then a_(1), a_(2) + a_(2) a_(3) + "………" + a_(n-1)a_(n) will be equal to :

If a_(1), a_(2), ……., a_(n) are in A.P. with common differece d != 0 , then (sin d) [sec a_(1) sec a_(2) + sec a_(2) sec a_(3) + .... + sec a_(n - 1) sec a_(n)] is equal to

If a_(0) = 0.4 and a_(n+1) = 2|a_(n)|-1 , then a_(5) =

If a_(1), a_(2), a_(3), ……. , a_(n) are in A.P. and a_(1) = 0 , then the value of (a_(3)/a_(2) + a_(4)/a_(3) + .... + a_(n)/a_(n - 1)) - a_(2)(1/a_(2) + 1/a_(3) + .... + 1/a_(n - 2)) is equal to

If a_(1) , a_(2), a_(3) , cdots ,a_(n) are in A.P. with a_(1) =3, a_(n) =39 and a_(1) +a_(2) + cdots +a_(n) =210 then the value of n is equal to

STATEMENT-1 : If a, b, c are in A.P. , b, c, a are in G.P. then c, a, b are in H.P. STATEMENT-2 : If a_(1) , a_(2) a_(3) ……..a_(100) are in A.P. and a_(3) + a_(98) = 50 " then" a _(1) + a_(2) +a_(3) + ….+ a_(100) = 2500 STATEMENT-3 : If a_(1) , a_(2) , ....... ,a_(n) ne 0 then (a_(1) + a_(2)+ a_(3) + .......+ a_(n))/(n) ge (a_(1) a_(2) .........a_(n) )^(1//n)

STATEMENT-1 : If a, b, c are in A.P. , b, c, a are in G.P. then c, a, b are in H.P. STATEMENT-2 : If a_(1) , a_(2) a_(3) ……..a_(100) are in A.P. and a_(3) + a_(98) = 50 " then" a _(1) + a_(2) +a_(3) + ….+ a_(100) = 2500 STATEMENT-3 : If a_(1) , a_(2) , ....... ,a_(n) ne 0 then (a_(1) + a_(2)+ a_(3) + .......+ a_(n))/(n) ge (a_(1) a_(2) .........a_(n) )^(1//n)