" Saumeto "17'7sin^(2)theta+3cos^(2)theta=4," show that "tan theta=(1)/(sqrt(3))

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If 7sin^(2)theta+3cos^(2)theta=4, show that tan theta=(1)/(sqrt(3))

If 7sin^(2)theta+3cos^(2)theta=4 then show that tan theta=(1)/(sqrt(3))

If 7sin^2theta+3cos^2theta=4 , show that tantheta=1/sqrt(3)

if 3cos^(2)theta+7sin^(2)theta=4, show that cot theta=sqrt(3)

If 7sin ^2theta +3cos^2theta =4 , prove that, tan theta =pm1/sqrt(3) .

If 7sin^(2)theta+3cos^(2)theta=4 , then find tan theta .

If 7sin^(2)theta+3cos^(2)theta=4 and theta is acute then show that cot theta=sqrt(3)

If 7sin^(2)theta +3cos^(2)theta = 4 and 'theta' is acute show that cot theta = sqrt(3) .

If sin^4theta+sin^2 theta=1 show that, tan^4theta-tan^2theta=1 .

(sin theta-2sin^(3)theta)/(2cos^(3)theta-cos theta)=tan theta