If `F_1` and `F_2` are the feet of the perpendiculars from the foci `S_1a n dS_2` of the ellipse `(x^2)/(25)+(y^2)/(16)=1` on the tangent at any point `P` on the ellipse, then prove that `S_1F_1+S_2F_2geq8.`

If F_(1) and F_(2) are the feet of the perpendiculars from the foci S_(1)andS_(2) of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 on the tangent at any point P on the ellipse,then prove that S_(1)F_(1)+S_(2)F_(2)>=8

If M_(1) and M_(2) are the feet of the perpendiculars from the foci S_(1) and S_(2) of the ellipse (x^(2))/(9)+(y^(2))/(16)=1 on the tangent at any point P on the ellipse, then (S_(1) M_(1)) (S_(2) M_(2))=

If F_1" and "F_2 be the feet of perpendicular from the foci S_1" and "S_2 of an ellipse (x^2)/(5)+(y^2)/(3)=1 on the tangent at any point P on the ellipse then (S_1F_1)*(S_2F_2) is

If M_(1) and M_(2) are the feet of perpendiculars from foci F_(1) and F_(2) of the ellipse (x^(2))/(64)+(y^(2))/(25)=1 on the tangent at any point P of the ellipse then

If F_(1) and F_(2) are the feet of the perpendiculars from foci S_(1) and S_(2) of the ellipse (x^(2 /(25 +y^(2 /(16 =1 on the tangent at any point P of the ellipse,then the minimum value of S_(1 F_(1 +S_(2 F_(2 is 1) 2, 2) 3, 3) 6, 4) 8

The product of the perpendiculars from the two foci of the ellipse (x^(2))/(9)+(y^(2))/(25)=1 on the tangent at any point on the ellipse

If p is the length of the perpendicular from the focus S of the ellipse x^(2)/a^(2)+y^(2)/b^(2) = 1 to a tangent at a point P on the ellipse, then (2a)/(SP)-1=

If F_(1), F_(2), F_(3) be the feet of the perpendicular from the foci S_(1), S_(2) of an ellipse x^(2)//5+y^(2)//3=1 on the tangent at any point P on the ellipse then S_(1)F_(1)*S_(2)F_(2)=