[3 lambdavec c+2 mu(vec a timesvec b)=0," then "],[[" 1) "3 lambda+2 mu=0],[" (3) "lambda=mu]]

If 3 lambdavec c+2 mu(vec a xxvec b)=0, then

vec i*(vec i timesvec i)=

(vec i timesvec j).vec k=

Solve (vec a timesvec a)*vec b

The vector equation of the plane passing through the origin and the line of intersection of the planes vec rdot vec a=lambdaa n d vec rdot vec b=mu is (a) vec rdot(lambda vec a-mu vec b)=0 (b) vec rdot(lambda vec b-mu vec a)=0 (c) vec rdot(lambda vec a+mu vec b)=0 (d) vec rdot(lambda vec b+mu vec a)=0

The vector equation of the plane passing through the origin and the line of intersection of the planes vec rdot vec a=lambdaa n d vec rdot vec b=mu is (a) vec rdot(lambda vec a-mu vec b)=0 (b) vec rdot(lambda vec b-mu vec a)=0 (c) vec rdot(lambda vec a+mu vec b)=0 (d) vec rdot(lambda vec b+mu vec a)=0

If vec a = i+j+k, vec b = i+j, vec c = i and (vec a xx vec b) xx vec c = lambda vec a + mu vec b , then lambda + mu

If [ 2 vec (a) - 3 vec(b) vec( c ) vec(d)] =lambda [vec(a) vec(c ) vec(d) ] + mu [ vec(b) vec( c ) vec( d) ] , then 2 lambda + 3 mu=

vec a = hat i + hat j + hat k, vec b = hat i + hat j, vec c = hat i and (vec a * vec b) * vec c = lambdavec a + muvec b then show that lambda + mu = 0