Calculate change in entropy when `5g` of pure ice melts to form water at `0^(@)C` Given latent heat of ice is `80cal//g` at `0^(@)C`.

Calculate the entropy change when 20.0 g of ice changes to liquid water at 0°C. The heat of fusion is 80.0 cal g^(-1) .

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

Calculate the amount of heat required to convert 10g of ice at - 10^@C to water at 5^@C (latent heat of fusion of ice = 80 cal g^(-1) , specific heat of ice = 0.5).

Calculate the amount of heat absorbed by 100 g of ice to change into water of 30^@ C.(Latent heat of fusion of ice is 80 cal//g )

When 1 g of ice at 0^(@)C melts to form 1 g of water at 0^(@)C then, is the latent heat absorbed by the ice or given out by it?

10 g of ice at 0 C is slowly melted to water at 0 C. The latent heat of melting is 80 cal /g. the change in entropy is ?(cal/k)