`1` mol of `N_(2)` is mixed with `3` mol of `H_(2)` in a litre container. If `50%` of `N_(2)` is converted into ammonia by the reaction `N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)`, then the total number of moles of gas at the equilibrium are

For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

One mole of N_(2) and 3 moles of H_(2) are mixed in a litre flask. If 50% N_(2) is converted into ammonia by the reaction. N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g) then the total number of moles of gas at equilibrium is :

For a reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))

2 moles of N_2 and 5 moles of H_2 are mixed in a one litre flask. If 75% of N_2 is converted into ammonia by the reaction N_2(g) + 3H_2(g) iff 2NH_3(g) , then the total number of moles of gas at equilibrium Is :

For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………

For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………

For the reaction N_(2)(G)+3H_(2)(g)hArr2NH_(3)(g),Delta=-93.6KJmol^(-1) The number of moles of H_(2) at equilibrium will increase If :

One mole of N_(2) (g) is mixed with 2 moles of H_(2)(g) in a 4 litre vessel If 50% of N_(2) (g) is converted to NH_(3) (g) by the following reaction : N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) What will the value of K_(c) for the following equilibrium ? NH_(3)(g)hArr(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)

One mole of N_(2) (g) is mixed with 2 moles of H_(2)(g) in a 4 litre vessel If 50% of N_(2) (g) is converted to NH_(3) (g) by the following reaction : N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) What will the value of K_(c) for the following equilibrium ? NH_(3)(g)hArr(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)