[" If "K(p)(PbSO(4))=1.8times10^(-5)" an...

[" If "K_(p)(PbSO_(4))=1.8times10^(-5)" and "K_(2)(HSO_(9)^(9))=1.0times10^(-3)the" equilibrium constant for the reactic "],[pbso_(4)+H^(e)(aq)rightleftharpoons HsO_(8)(aq)+Pb^(2)(aq)" is "]

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If K_(sp) (PbSO_(4)) =1.8 xx 10^(-8) and K_(a) (HSO_(4)^(Theta)) = 1.0 xx 10^(-2) the equilibrium constant for the reaction. PbSO_(4)(s) +H^(o+)(aq) hArr HSO_(4)^(Theta)(aq) +Pb^(2+)(aq) is

Equilibrium const. {:(H_2S(aq)hArr H^+(aq)+HS^(-)(aq)," " K_1=9.5xx10^(-8)),(HS^(-)(aq)hArr H^+(aq)+S^(2-)(aq)," " K_2=1.0xx10^(-19)):} What is the equilibrium constant for the reaction ? S^(2-)(aq)+2H^(+)(aq) hArr H_2S(aq) " " K=?

Given K_(a) values of 5.76xx10^(-10) and 4.8xx10^(-10) for NH_(4)^(+) and HCN respectively. What is the equilibrium constant for the following reaction? NH_(4)^(+)(aq.)+CN^(-)(aq.)hArrNH_(3)(aq.)+HCN(aq.)

Given : BaF_(2) (s) harr Ba^(+2) (aq)+2 F^(-) (aq); K_(sp) = 1.0times10^(-8) M^(3) HF(aq) harr H^(+) (aq)+ F^(-) (aq); K_(a) = 6.5times10^(-6) M The value of K_(c) for BaF_(2) (s)+ 2H^(+)(aq) harr Ba^(+2)(aq) + 2HF(aq) is:

Equilibrium constant for reaction NH_(4)OH(aq)+H^(+)(aq)hArr NH_(4)^(+)(aq)+H_(2)O(l) 1.8xx19^(9) . Hence equilibrium constant for ionization NH_(3)+H_(2)OhArr NH_(4)^(+)(aq)+OH^(-)(aq) is x xx 10^(-6) . The value of 'x' is

[" If "K_(p)(PbSO_(4))=1.8times10^(-5)" and "K_(2)(HSO_(9)^(9))=1.0times10^(-3)the" equilibrium constant for the reactic "],[pbso_(4)+H^(e)(aq)rightleftharpoons HsO_(8)(aq)+Pb^(2)(aq)" is "]

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