[" The equation of line belonging to the family of lines "p(2x+3y-13)+q(x-y+1)=0" ,"],[p,q in R," and which is at maximum distance from the origin is "],[" 1) "4x+3y-17=0" 2) "3x+2y-12=0" 3) "2x+3y-13=04" ) "x+y-5=0]

The equation of line belonging to the family of lines (5x+3y-2)+lambda(3x-y-4)=0 , lambda in R ,and at greatest distance from (0,0) is

That line of the family p(2x+3y-13)+q(x-y+1)=0 which is farthest from the origin is :

The equation of the line passing through the point of intersection of the lines 2x+3y-4=0, 3x-y+5=0 and the origin is

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

Find the equation of the line through the intersection of the lines 2x-3y=0 and 4x-5y=2 and which is perpendicular to the line x+2y+1=0.

Equation of straight line ax+by+c=0 where 3a+4b+c=0, which is at maximum distance from (1,-2), is 3x+y-17=04x+3y-24=03x+4y-25=0(d)x+3y-15=0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0