the value of `lambda` for which the line `2x-8/3lambday=-3` is a normal to the conic `x^2+y^2/4=1` is:

the value of lambda for which the line 2x-(8)/(3)lambda y=-3 is a normal to the conic x^(2)+(y^(2))/(4)=1 is:

Find the value of m, for which the line y=mx + 25sqrt3/3 is a normal to the conic x^2 /16 - y^2 / 9 =1 .

Find the value of m, for which the line y=mx + 25sqrt3/3 is a normal to the conic x^2 /16 - y^2 / 9 =1 .

The value of m, for wnich the line y=mx + 25sqrt3/3 is a normal to the conic x^2 /16 - y^2 / 9 =1 , IS

The value for m for which the line y=m x+(25)/(sqrt(3)) is a normal to the conic (x^(2))/(16)-(y^(2))/(9)=1 is

The value of m, for wnich the line y=mx+25(sqrt(3))/(3) is a normal to the conic (x^(2))/(16)-(y^(2))/(9)=1, IS

Find the value of lambda so that the line 3x-4y= lambda may touch the circle x^2+y^2-4x-8y-5=0