[" Et A hoop rolls on a horizontal "],[" ground without Slipping with "],[" linear speed "u" .Speed of a "],[" particle "P" on the circumference "],[" of the hoop at angle "theta" is "],[([0],[0],[1])],[(p)/(1)*(p)/(1+hat theta))]

A hoop rolls on a horizontal ground without slipping with linear speed v . Speed of a particle P on the circumference of the hoop at angle theta is :

A hoop rolls on a horizontal ground without slipping with linear speed v . Speed of a particle P on the circumference of the hoop at angle theta is :

A disc rolls over a horizontal floor without slipping with a linear speed of 5 cm/sec. Then the linear speed of a particle on its rim, with respect to the floor, when it is in its highest position is?

A disc rolls over a horizontal floor without slipping with a linear speed of 5 cm/sec. Then the linear speed of a particle on its rim, with respect to the floor, when it is in its highest position is?

A ring of radius R rolls on a horizontal ground with linear speed v and angular speed omega . For what value of theta the velocity of point P is in vertical direction (vltRomega) .

A ring of radius R rolls on a horizontal ground with linear speed v and angular speed omega . For what value of theta the velocity of point P is in vertical direction (vltRomega) .

A smooth hoop lie as on a smooth horizontal table and is fixed. A particle is projected on the table form a point A on the inner circumference of the hoop at angle theta with radius vector . If e be the coefficient of restitution and the particle returns to the point of projection after two successive impacts. The final angle theta' made by velocity vector with radius of hoop is

A disc rolls on ground without slipping . Velocity of centre of mass is v. There is a point P on circumference of disc at angle theta . Suppose v_(p) is the speed of this point. Then, match the following the following table.