[" The coefficient of friction between the tyres and road is "],[0.4." The minimum distance covered before attaining a speed "],[" of "8m/s" starting from rest is nearly: "(g=10m/s^(2))]

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly (take, g=10 ms^(-2) )

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2) )

A car starts with a velocity of 100m//s on a half kilometre long bridge The coefficient of friction between the tyres and road is 0.1 Show that one cannot drive throught the bridge in less than 10 s Take g = 10m//s^(2) .

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is ("Take g"=10ms^(-2))

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is ("Take g"=10ms^(-2))

A vac moving with a speed of 108 km //h on level road where coefficient of friction between tyres and rod is 0.5 .For the safe driving of van the minimum radius of curvature of the rod will be (g=10 m//s^(2))

A van is moving with a speed of 108 km / hr on level road where the coefficient of fraction between the tyres and the road is 0.5 for the safe driving of the van , the minimum radius of curvature of the road will be ( g=10 m//s^(2) )

[" The coefficient of "],[" friction between car "],[" wheels and a road is "],[0.5" .The least "],[" distance in which the "],[" car can accelerate "],[" from rest to "72kmph],[" is "(g=10m/s^(2))]