A body of mass `m=10^(-2) kg` is moving in a medium and experiences a frictional force `F=-KUPSILON^(2).` Its initial speed is `upsilon_(0)=10ms^(-2)`. If , after `10s`, its energy is `(1)/(8)m upsilon_(0)^(2)`, the value of `k` will be

A body of mass m = 10^(-2) kg is moving in a medium and experiences a frictional force F = - kv^(2) . Its initial speed is v_(0) = 10 m cdot s^(-1) . If after 10 s, its energy is (1)/(8)mv_(0)^(2) the value of k will be

A body of mass m= 10^(-2) kg is moving in a medium and experiences a frictional force F =-kv^2 . Its initial speed is v_0=10m*s^(-1) . If after 10 s ,its energy is 1/8 mv_0^2 , the value of k will be

A body of mass m = 1 kg is moving in a medium and experiences a frictional force F = -kv, where v is the speed of the body. The initial speed is v_(0) = 10 ms^(-1) and after 10 s, its energy becomes half of the initial energy. Then, the value of k is

A body of mass m = 1 kg is moving in a medium and experiences a frictional force F = -kv, where v is the speed of the body. The initial speed is v_(0) = 10 ms^(-1) and after 10 s, its energy becomes half of the initial energy. Then, the value of k is

A body of mass 10 kg is being acted upon by a force 3t^2 and an opposing constant force of 32 N. The initial speed is 10 ms^-1. The velocity of body after 5 s is

A body of mass 10 kg is being acted upon by a force 3t^2 and an opposing constant force of 32 N. The initial speed is 10 ms^-1. The velocity of body after 5 s is

A body of mass 10 kg moving at a height of 2 m, with uniform speed of 2 m/s. Its total energy is

A body of mass 5 kg is taken a height 5 m to 10 m .Find the increase in its potential energy (g=10 m s^(-2) )