A particle performs simple harmonic mition with amplitude A. Its speed is trebled at the instant that it is at a destance
`(2A)/3` from equilibrium position. The new amplitude of the motion is:

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance (2A)/3 from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion with amplitude A. Its speed is tripled at the instant that it is at a distance (2A)/3 from equilibrium position. The new amplitude of the motion is:

A particle performs simple harmonic motion wit amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion wit amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion with amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is (sqrt(33)A)/(beta) . Find beta

A particle performs simple harmonic motion with amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is (sqrt(33)A)/(beta) . Find beta

A particle executes simple harmonic motion of amplitude A. At what points is its speed half the maximum speed ?