A moving coil galvanometer of resistance `100Omega` is used as an ammeter using a resistance `0.1 Omega`. The maximum diflection current in the galvanometer is `100 muA`. Find the minimum current in the circuit so that the ammeter shows maximum deflection

A galvanometer of resistance 36 Omega is changed into an ammeter by using a shunt of 4 Omega . The fraction f of total current passing through the galvanometer is

A galvanometer has resistance 1 Omega . Maximum deflection current through it is 0.1 A

A galvanometer of resistance 50Omega is converted into an ammeter by connecting a low resistance (shunt) of value 1Omega in parallel to the galvanometer, S. If full - scale deflection current of the galvanometer is 10 mA, then the maximum current that can be measured by the ammeter is -

A galvanometer of resistance 50Omega is converted into an ammeter by connecting a low resistance (shunt) of value 1Omega in parallel to the galvanometer, S. If full - scale deflection current of the galvanometer is 10 mA, then the maximum current that can be measured by the ammeter is -

A galvanometer of resistance 100 Omega gives the full scale deflection for a current of 10 m A. If a resistance of 1 Omega is connected in parallel to the coil of the galvanometer , then maximum current that can be measured with the galvanometer will be

A galvanometer of resistance 100 Omega gives full-scale defletion for a current of 10muA . Find the resistance needed to convert it to an ammeter of range 1A.