Two progressive waves having equation `x_(1) = 3 sin omegatau` and `x_(2) = 4 sin (omegatau + 90^(@))` are superimposed. The amplitude of the resultant wave is

two waves y_1 = 10sin(omegat - Kx) m and y_2 = 5sin(omegat - Kx + π/3) m are superimposed. the amplitude of resultant wave is

two waves y_1 = 10sin(omegat - Kx) m and y_2 = 5sin(omegat - Kx + π/3) m are superimposed. the amplitude of resultant wave is

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2x - 6t) and y_(2) = 3 sin (2x - 6t - (pi)/(2)) are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2 x - 6t) and y_(2) = 3 sin (2x - 6t -(pi)/(2)) are superposed, the amplitude of the resultant wave is

The equations for displacement of two light waves forming interference pattern are y_(1) = 4 sin omega t and y_(2) =3 sin (omega t+ (pi)/(2)) . Determine the amplitude of the resultant wave.