Let f be a one-one function with domain `{x,y,z}` and range `{1,2,3}`. It is given that exactly one of the following statements is true and the remaining two are false `f(X)=1, f(y)!=1 f(z)!=2` determine `f^(-1)(1)`

Consider that f : A rarr B (i) If f(x) is one-one f(x_(1)) = f(x_(2)) hArr x_(1) = x_(2) or f'(x) ge 0 or f'(x) le 0 . (ii) If f(x) is onto the range of f(x) = B. (iii) If f(x) and g(x) are inverse of each other then f(g(x)) = g(f(x)) = x. Now consider the answer of the following questions. Let f be one-oe function with domain {x, y, z} and range {1, 2, 3}. It is given that exactly one of the following statement is true and the remaining two are false. f(x) = 1, f(y) != 1, f(z) != 2 , then the value of f^(-1)(1) is

Consider that f : A rarr B (i) If f(x) is one-one f(x_(1)) = f(x_(2)) hArr x_(1) = x_(2) or f'(x) ge 0 or f'(x) le 0 . (ii) If f(x) is onto the range of f(x) = B. (iii) If f(x) and g(x) are inverse of each other then f(g(x)) = g(f(x)) = x. Now consider the answer of the following questions. Let f be one-oe function with domain {x, y, z} and range {1, 2, 3}. It is given that exactly one of the following statement is true and the remaining two are false. f(x) = 1, f(y) != 1, f(z) != 2 , then the value of f^(-1)(1) is

Let f be a one-one function with domain (21, 22, 23) and range {x,y,z). It is given that exactly one of the following statements is true and the remaining two are false. f(21) = x; f(22)!=x ; f(23) != y. Then f^(-1)(x) is

Let f be a one-one function with domain (21,22,23) and range {x,y,z). It is given that exactly one of the following statements is true and the remaining two are false.f(21)=x;f(22);f(23)!=y. Then f^(-1)(x) is

Let f be an injective function with domain {x, y, z} and range {1, 2, 3} such that exactly one of the following statements is correct and the remaining are false. f(x)=1, f(y) ne1, f(z) ne 2 . The value of f^(-1)(1) is

Let 'f' be an injective mapping with domain {x,y,z} and range {1,2,3} such that exactly one of the following statements is correct and the remaining are false f(x)=1, f(y) != 1, f(z) != 2, then f^(-1)(1)=

Let f be an injective map with domain {x ,\ y ,\ z} and range {1, 2, 3} such that exactly one of the following statements is correct and the remaining are false. f(x)=1,\ \ f(y)!=1,\ f(z)!=2 . The value of f^(-1)(1) is (a) x (b) y (c) z (d) none of these