A simple harmonic motion is given by `y = 5(sin3pit + sqrt(3) cos3pit)`. What is the amplitude of motion if `y` is in `m` ?

An SHM is give by y=5["sin"(3pit)+sqrt(3)"cos"(3pit)] . What is the amplitude of the motion of y in metre ?

A simple harmonic motion is represented by : y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm The amplitude and time period of the motion are :

A simple harmonic motion is represented by : y=5(sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

A simple harmonic motion is represented by : y=59sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by