`A = (1,2), B(3,4)` and the locus of `C` is `2x + 3y = 5` then the locus of the centroid of `DeltaΑΒC` is

A=(1,2),B(3,4) and the locus of C is 2x+3y=5 then the locus of the centroid of Delta ABC is

A=(2,5),B=(4,-11) and the locus of ^ prime C' is 9x+7y+4=0 then the locus of the centroid of ABC is

If A (2, -3) and B (-2, 1) are two vertices of a triangle and third vertex moves on the line 2x + 3y = 9, then the locus of the centroid of the triangle is :

If A(2, -3) and B(-2, 1) are two vertices of a triangle and third vertex moves on the line 2x+3y=9 , then the locus of the centroid of the triangle is :

A(2, 3), B(3, -5) are two vertices of DeltaABC . C is a point the line L-=3x+4y-5=0 . Then the locus of the centroid of DeltaABC is a line parallel to

If the points P(6,2) and Q(-2,1) and R are the vertices of a DeltaPQR and R is the point on the locus of y=x^(2)-3x+4 , then find the equation of the locus of centroid of DeltaPQR .