The plates of parallel capaitor are given charges `+4Q` and `-2Q`. The capacitor is then connected across an uncharged capacitor of sae capacitances first one `(=C)`. Find the final potential difference between the plates of the first capacitor.

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

In a parallel plate capacitor of capacitor 1muF two plates are given charges 2muC and 4muC the potential difference between the plates of the capacitor is

In a parallel plate capacitor of capacitor 1muF two plates are given charges 2muC and 4muC the potential difference between the plates of the capacitor is

In an isolated parallel plate capacitor of capacitance C , the plates have charge Q_(1) and Q_(2) . The potential difference between the plates is

Two parallel conducting plates of a capacitor of capacitance C containing charges Q and -2Q at a distance d apart. Find out potential difference between the plates of capacitors.

Two parallel conducting plates of a capacitor of capacitance C containing charges Q and -2Q at a distance d apart. Find out potential difference between the plates of capacitors.

Consider a parallel plate capacitor originally with a charge q_0 capacitance C_0 and potential difference Delta V_0 There is an electrostatic force of magnitude F_0 between the plates and the capacitor has a stored energy U_0 . The terminals of the capacitor are connected to another capacitor of same capacitance and charge. A dielectric slab with k_e gt 1 is inserted between the plates of the first capacitor . Which quantity decreases?