IF `phi(n+1)=(2phi(n)+1)/2` , for all `n in N` and `phi(1)=2` then `phi(2007)` is

If phi (x)=phi '(x) and phi(1)=2 , then phi(3) equals

If phi(x)=phi'(x) and phi(1)=2, then phi(3) equals

Define a function phi:NtoN as follows phi(1)=1,phi(P^(n))=P^(n-1)(P-1) is prime and n epsilonN and phi(mn)=phi(m)phi(n) if m & n are relatively prime natural numbers. phi(8n+4) when n epsilonN is equal to

Define a function phi:NtoN as follows phi(1)=1,phi(P^(n))=P^(n-1)(P-1) is prime and n epsilonN and phi(mn)=phi(m)phi(n) if m & n are relatively prime natural numbers. The number of natural numbers n such that phi(n) is odd is

Define a function phi:NtoN as follows phi(1)=1,phi(P^(n))=P^(n-1)(P-1) is prime and n epsilonN and phi(mn)=phi(m)phi(n) if m & n are relatively prime natural numbers. If phi(7^(n))=2058 where n epsilon N then the valule of n is

Define a function phi:NtoN as follows phi(1)=1,phi(P^(n))=P^(n-1)(P-1) is prime and n epsilonN and phi(mn)=phi(m)phi(n) if m & n are relatively prime natural numbers. If phi(7^(n))=2058 where n epsilon N then the valule of n is