A particle executes simple harmonic motion with a time period of 16s. At time `t=4s` its velocity is `4ms^(-1)`. Find its amplitute of motion.

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscilltes is

A particle is executing simple harmonic motion with a time period T . At time t=0, it is at its position of equilibium. The kinetice energy -time graph of the particle will look like

A particle is executing simple harmonic motion with a time period T . At time t=0, it is at its position of equilibium. The kinetice energy -time graph of the particle will look like

A particle is executing simple harmonic motion with a time period T . At time t=0, it is at its position of equilibium. The kinetice energy -time graph of the particle will look like

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscillates is