After charging a capacitor the battery is removed. Now by placing a dielectric slab between the plates

Two capacitors A and B of capacities C and 2C are connected in parallel and the combination is connected to a battery of V volts. After the charging is over , the battery is removed. Now a dielectric slab of K=2 is inserted between the plates of A so as fill the completely. The energy lost by the system during the sharing of charges is (i) With battery of parallel combination :

A parallel plate capacitor (C=50 muF. d=4mm) is charged to 200V and then charging battery is removed. Now a dielectric slab (K=4) of thickness 2mm is placed between the plates. Find new potential difference across capacitor.

A parallel plate capacitor (C=50 muF. d=4mm) is charged to 200V and then charging battery is removed. Now a dielectric slab (K=4) of thickness 2mm is placed between the plates. Find new potential difference across capacitor.

A parallel plate capacitor is charged by a battery after charging the capacitor, battery is disconnected and if a dielectric plate is inserted between the place of plates. Then which one of the following statements is not correct :

A parallel plate capacitor is charged by a battery. The battery is removed and a thick glass slab is inserted between the plates. Now,

While a capacitor remains connected to a battery and dielectric slab is applied between the plates, then