In the potentiometer circuit shown in the figure the balance length AJ=60cm when switch S is open. When switch S is closed and the value of R=`5Omega`, the b alance length AJ=50cm. The internal resistance of the cell C' is

In the circuit shown, the reading of ammeter when switch S is open and when switch S is closed respectively are

In the circuit shown in the Figure find the equivalent capacitance between points a and b when– (a) Switch S is open. (b) Switch S is closed.

Consider the potentiometer circuit for determining the internal resistance of a cell. When switch S is open, the balance point is found to be at 75 cm os the wire. When switch S is closed and value of R is 4 Omega , the balance points shifts to 60 cm . find the internal resistance of cell. .

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

What is the current in the 4Omega resistor when switch S_(1) is open and switch S_(2) is closed in the given circuit ?