In a triangle `A B C ,` side `A B` has equation `2x+3y=29` and side `A C` has equation `x+2y=16.` If the midpoint of `B C` is 5, 6), then find the equation of `B Cdot`

In a triangle ABC, side AB has equation 2x+3y=29 and side AC has equation x+2y=16. ft the midpoint of BC is 5,6) then find the equation of BC.

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BC is (5,6) then find the equation of BC

The sides AB and AC of a triangle ABC are respectively 2x+3y=29 and x+2y=16 respectively.If the mid-point of BCis(5,6) then find the equation of BC.

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot