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f(x)=|[1,x,(x+1)],[2x,x(x-1),(x+1)x],[3x...

f(x)=|[1,x,(x+1)],[2x,x(x-1),(x+1)x],[3x(x-1),x(x-1)(x-2),x(x-1)(x+1)]|" then,"f(50)+f(51)+cdots+f(99)=

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